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2012103120023 is a prime number
BaseRepresentation
bin11101010001111010101…
…100010001010010010111
321010100120221000001101122
4131101322230101102113
5230431241344320043
64140203012514155
7265240535220203
oct35217254212227
97110527001348
102012103120023
11706367835017
12285b6131b95b
13117981b92859
146d55a071b03
153751581c368
hex1d47ab11497

2012103120023 has 2 divisors, whose sum is σ = 2012103120024. Its totient is φ = 2012103120022.

The previous prime is 2012103119951. The next prime is 2012103120107. The reversal of 2012103120023 is 3200213012102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2012103120023 - 214 = 2012103103639 is a prime.

It is a super-2 number, since 2×20121031200232 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2012103119983 and 2012103120010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2012103120523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006051560011 + 1006051560012.

It is an arithmetic number, because the mean of its divisors is an integer number (1006051560012).

Almost surely, 22012103120023 is an apocalyptic number.

2012103120023 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012103120023 is an equidigital number, since it uses as much as digits as its factorization.

2012103120023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2012103120023 its reverse (3200213012102), we get a palindrome (5212316132125).

It can be divided in two parts, 201210 and 3120023, that added together give a palindrome (3321233).

The spelling of 2012103120023 in words is "two trillion, twelve billion, one hundred three million, one hundred twenty thousand, twenty-three".