Base | Representation |
---|---|
bin | 101110100100011011100… |
… | …011110100111010000110 |
3 | 102022221022100101002121122 |
4 | 232210123203310322012 |
5 | 404413014012341402 |
6 | 10450054011113542 |
7 | 450131155531451 |
oct | 56443343647206 |
9 | 12287270332548 |
10 | 3200213012102 |
11 | 10242258a8037 |
12 | 438280a428b2 |
13 | 1a2a18010c32 |
14 | b0c693c6498 |
15 | 583a1742ca2 |
hex | 2e91b8f4e86 |
3200213012102 has 4 divisors (see below), whose sum is σ = 4800319518156. Its totient is φ = 1600106506050.
The previous prime is 3200213011993. The next prime is 3200213012173. The reversal of 3200213012102 is 2012103120023.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 800053253024 + ... + 800053253027.
It is an arithmetic number, because the mean of its divisors is an integer number (1200079879539).
Almost surely, 23200213012102 is an apocalyptic number.
3200213012102 is a deficient number, since it is larger than the sum of its proper divisors (1600106506054).
3200213012102 is a wasteful number, since it uses less digits than its factorization.
3200213012102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1600106506053.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 3200213012102 its reverse (2012103120023), we get a palindrome (5212316132125).
The spelling of 3200213012102 in words is "three trillion, two hundred billion, two hundred thirteen million, twelve thousand, one hundred two".
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