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2012113011300 = 22352717229246121
BaseRepresentation
bin11101010001111011010…
…010000000001001100100
321010100121121121120200020
4131101323102000021210
5230431301412330200
64140204004515140
7265241015254560
oct35217322001144
97110547546606
102012113011300
11706372380527
12285b646abab0
13117983c46a92
146d55b4c86a0
1537516622ea0
hex1d47b480264

2012113011300 has 288 divisors, whose sum is σ = 7075554635520. Its totient is φ = 430965964800.

The previous prime is 2012113011277. The next prime is 2012113011313. The reversal of 2012113011300 is 31103112102.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 2012113011300.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 8052240 + ... + 8298360.

It is an arithmetic number, because the mean of its divisors is an integer number (24567898040).

Almost surely, 22012113011300 is an apocalyptic number.

2012113011300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2012113011300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3537777317760).

2012113011300 is an abundant number, since it is smaller than the sum of its proper divisors (5063441624220).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2012113011300 is a wasteful number, since it uses less digits than its factorization.

2012113011300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 246391 (or 246384 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 2012113011300 its reverse (31103112102), we get a palindrome (2043216123402).

The spelling of 2012113011300 in words is "two trillion, twelve billion, one hundred thirteen million, eleven thousand, three hundred".