Base | Representation |
---|---|
bin | 1001001001101000010101… |
… | …01100000101010011111011 |
3 | 2122020122122211020120020111 |
4 | 10210310022230011103323 |
5 | 10114140030341010021 |
6 | 110443544324405151 |
7 | 4144526265233305 |
oct | 444641254052373 |
9 | 78218584216214 |
10 | 20122101110011 |
11 | 645880a54920a |
12 | 230b96ab467b7 |
13 | b2c676887264 |
14 | 4d7cb465c975 |
15 | 24d64e5228e1 |
hex | 124d0ab054fb |
20122101110011 has 2 divisors, whose sum is σ = 20122101110012. Its totient is φ = 20122101110010.
The previous prime is 20122101109987. The next prime is 20122101110029. The reversal of 20122101110011 is 11001110122102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20122101110011 - 223 = 20122092721403 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20122101109973 and 20122101110000.
It is not a weakly prime, because it can be changed into another prime (20122101110071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061050555005 + 10061050555006.
It is an arithmetic number, because the mean of its divisors is an integer number (10061050555006).
Almost surely, 220122101110011 is an apocalyptic number.
20122101110011 is a deficient number, since it is larger than the sum of its proper divisors (1).
20122101110011 is an equidigital number, since it uses as much as digits as its factorization.
20122101110011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 20122101110011 its reverse (11001110122102), we get a palindrome (31123211232113).
The spelling of 20122101110011 in words is "twenty trillion, one hundred twenty-two billion, one hundred one million, one hundred ten thousand, eleven".
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