Base | Representation |
---|---|
bin | 1001001001101000010110… |
… | …10010111101000110101101 |
3 | 2122020122200112102021021222 |
4 | 10210310023102331012231 |
5 | 10114140040443100023 |
6 | 110443545331033125 |
7 | 4144526450653622 |
oct | 444641322750655 |
9 | 78218615367258 |
10 | 20122111300013 |
11 | 64588152790a8 |
12 | 230b97243b7a5 |
13 | b2c678a14448 |
14 | 4d7cb5b52349 |
15 | 24d650386cc8 |
hex | 124d0b4bd1ad |
20122111300013 has 8 divisors (see below), whose sum is σ = 20936300779800. Its totient is φ = 19315943391808.
The previous prime is 20122111300007. The next prime is 20122111300021. The reversal of 20122111300013 is 31000311122102.
It can be written as a sum of positive squares in 4 ways, for example, as 6331977060964 + 13790134239049 = 2516342^2 + 3713507^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20122111300013 is a prime.
It is a super-2 number, since 2×201221113000132 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20122111299964 and 20122111300000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20122111303013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2005387778 + ... + 2005397811.
It is an arithmetic number, because the mean of its divisors is an integer number (2617037597475).
Almost surely, 220122111300013 is an apocalyptic number.
It is an amenable number.
20122111300013 is a deficient number, since it is larger than the sum of its proper divisors (814189479787).
20122111300013 is a wasteful number, since it uses less digits than its factorization.
20122111300013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4010785791.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 20122111300013 its reverse (31000311122102), we get a palindrome (51122422422115).
The spelling of 20122111300013 in words is "twenty trillion, one hundred twenty-two billion, one hundred eleven million, three hundred thousand, thirteen".
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