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2012301400343 = 13154792415411
BaseRepresentation
bin11101010010000110100…
…000101001100100010111
321010101002202002201212012
4131102012200221210113
5230432143124302333
64140234414414435
7265245463453013
oct35220640514427
97111082081765
102012301400343
11706459752a53
12285bb780141b
131179b3c971a0
146d578527543
1537527e36e48
hex1d486829917

2012301400343 has 4 divisors (see below), whose sum is σ = 2167093815768. Its totient is φ = 1857508984920.

The previous prime is 2012301400339. The next prime is 2012301400391. The reversal of 2012301400343 is 3430041032102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2012301400343 - 22 = 2012301400339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2012381400343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77396207693 + ... + 77396207718.

It is an arithmetic number, because the mean of its divisors is an integer number (541773453942).

Almost surely, 22012301400343 is an apocalyptic number.

2012301400343 is a deficient number, since it is larger than the sum of its proper divisors (154792415425).

2012301400343 is a wasteful number, since it uses less digits than its factorization.

2012301400343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154792415424.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 2012301400343 its reverse (3430041032102), we get a palindrome (5442342432445).

The spelling of 2012301400343 in words is "two trillion, twelve billion, three hundred one million, four hundred thousand, three hundred forty-three".

Divisors: 1 13 154792415411 2012301400343