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20124873170471 is a prime number
BaseRepresentation
bin1001001001101101011111…
…11010101001111000100111
32122020220211000100211022102
410210312233322221320213
510114211220012423341
6110445123351322315
74144655055324236
oct444665772517047
978226730324272
1020124873170471
116459a02283273
12231040338039b
13b2c9c8c81314
144d809888cb1d
1524d762a8dc9b
hex124dafea9e27

20124873170471 has 2 divisors, whose sum is σ = 20124873170472. Its totient is φ = 20124873170470.

The previous prime is 20124873170351. The next prime is 20124873170473. The reversal of 20124873170471 is 17407137842102.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20124873170471 is a prime.

It is a super-3 number, since 3×201248731704713 (a number of 41 digits) contains 333 as substring.

Together with 20124873170473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20124873170473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10062436585235 + 10062436585236.

It is an arithmetic number, because the mean of its divisors is an integer number (10062436585236).

Almost surely, 220124873170471 is an apocalyptic number.

20124873170471 is a deficient number, since it is larger than the sum of its proper divisors (1).

20124873170471 is an equidigital number, since it uses as much as digits as its factorization.

20124873170471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 526848, while the sum is 47.

The spelling of 20124873170471 in words is "twenty trillion, one hundred twenty-four billion, eight hundred seventy-three million, one hundred seventy thousand, four hundred seventy-one".