Base | Representation |
---|---|
bin | 1001001001101101011111… |
… | …11010101001111000100111 |
3 | 2122020220211000100211022102 |
4 | 10210312233322221320213 |
5 | 10114211220012423341 |
6 | 110445123351322315 |
7 | 4144655055324236 |
oct | 444665772517047 |
9 | 78226730324272 |
10 | 20124873170471 |
11 | 6459a02283273 |
12 | 231040338039b |
13 | b2c9c8c81314 |
14 | 4d809888cb1d |
15 | 24d762a8dc9b |
hex | 124dafea9e27 |
20124873170471 has 2 divisors, whose sum is σ = 20124873170472. Its totient is φ = 20124873170470.
The previous prime is 20124873170351. The next prime is 20124873170473. The reversal of 20124873170471 is 17407137842102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20124873170471 is a prime.
It is a super-3 number, since 3×201248731704713 (a number of 41 digits) contains 333 as substring.
Together with 20124873170473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20124873170473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10062436585235 + 10062436585236.
It is an arithmetic number, because the mean of its divisors is an integer number (10062436585236).
Almost surely, 220124873170471 is an apocalyptic number.
20124873170471 is a deficient number, since it is larger than the sum of its proper divisors (1).
20124873170471 is an equidigital number, since it uses as much as digits as its factorization.
20124873170471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 526848, while the sum is 47.
The spelling of 20124873170471 in words is "twenty trillion, one hundred twenty-four billion, eight hundred seventy-three million, one hundred seventy thousand, four hundred seventy-one".
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