Base | Representation |
---|---|
bin | 1001001001110111000011… |
… | …00100001111001100110100 |
3 | 2122021102001101111202111211 |
4 | 10210323201210033030310 |
5 | 10114302220241401400 |
6 | 110451332253211204 |
7 | 4145226123231442 |
oct | 444734144171464 |
9 | 78242041452454 |
10 | 20130001122100 |
11 | 64610a3933221 |
12 | 23113b4790b04 |
13 | b3033548c21c |
14 | 4d8423939b92 |
15 | 24d962d6bdba |
hex | 124ee190f334 |
20130001122100 has 18 divisors (see below), whose sum is σ = 43682102435174. Its totient is φ = 8052000448800.
The previous prime is 20130001122053. The next prime is 20130001122107. The reversal of 20130001122100 is 122110003102.
It can be written as a sum of positive squares in 3 ways, for example, as 4716697865616 + 15413303256484 = 2171796^2 + 3925978^2 .
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20130001122107) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 100650005511 + ... + 100650005710.
Almost surely, 220130001122100 is an apocalyptic number.
20130001122100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
20130001122100 is an abundant number, since it is smaller than the sum of its proper divisors (23552101313074).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20130001122100 is a wasteful number, since it uses less digits than its factorization.
20130001122100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 201300011235 (or 201300011228 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 20130001122100 its reverse (122110003102), we get a palindrome (20252111125202).
The spelling of 20130001122100 in words is "twenty trillion, one hundred thirty billion, one million, one hundred twenty-two thousand, one hundred".
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