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20130001141 is a prime number
BaseRepresentation
bin10010101111110101…
…110111000011110101
31220221220011000021211
4102233311313003311
5312211240014031
613125251441421
71311561120655
oct225765670365
956856130254
1020130001141
11859a951888
123a995b6271
131b8a5c3aa3
14d8d686365
157cc399bb1
hex4afd770f5

20130001141 has 2 divisors, whose sum is σ = 20130001142. Its totient is φ = 20130001140.

The previous prime is 20130001103. The next prime is 20130001169. The reversal of 20130001141 is 14110003102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11043908100 + 9086093041 = 105090^2 + 95321^2 .

It is a cyclic number.

It is not a de Polignac number, because 20130001141 - 215 = 20129968373 is a prime.

It is a super-2 number, since 2×201300011412 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130001181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065000570 + 10065000571.

It is an arithmetic number, because the mean of its divisors is an integer number (10065000571).

Almost surely, 220130001141 is an apocalyptic number.

It is an amenable number.

20130001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130001141 is an equidigital number, since it uses as much as digits as its factorization.

20130001141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 20130001141 its reverse (14110003102), we get a palindrome (34240004243).

The spelling of 20130001141 in words is "twenty billion, one hundred thirty million, one thousand, one hundred forty-one".