2013011311 has 2 divisors, whose sum is σ = 2013011312. Its totient is φ = 2013011310.

The previous prime is 2013011309. The next prime is 2013011333. The reversal of 2013011311 is 1131103102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2013011311 - 2¹ = 2013011309 is a prime.

Together with 2013011309, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 2013011291 and 2013011300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013018311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006505655 + 1006505656.

It is an arithmetic number, because the mean of its divisors is an integer number (1006505656).

Almost surely, 2^2013011311 is an apocalyptic number.

2013011311 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013011311 is an equidigital number, since it uses as much as digits as its factorization.

2013011311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 2013011311 is about 44866.5945999917. The cubic root of 2013011311 is about 1262.6473503930.

Adding to 2013011311 its reverse (1131103102), we get a palindrome (3144114413).

The spelling of 2013011311 in words is "two billion, thirteen million, eleven thousand, three hundred eleven".