| Base | Representation |
|---|---|
| bin | 101101110001010100010010… |
| … | …011010110011010011100000 |
| 3 | 222101202012101221120000221022 |
| 4 | 231301110102122303103200 |
| 5 | 202341104204042241000 |
| 6 | 1552044244002545012 |
| 7 | 60254345455166321 |
| oct | 5561242232632340 |
| 9 | 871665357500838 |
| 10 | 201301131212000 |
| 11 | 5916036a728896 |
| 12 | 1a6b1611668168 |
| 13 | 88427cc844821 |
| 14 | 379d053514448 |
| 15 | 1841487463585 |
| hex | b715126b34e0 |
201301131212000 has 192 divisors, whose sum is σ = 495911401247808. Its totient is φ = 80306732800000.
The previous prime is 201301131211997. The next prime is 201301131212003. The reversal of 201301131212000 is 212131103102.
It is an interprime number because it is at equal distance from previous prime (201301131211997) and next prime (201301131212003).
It is a self number, because there is not a number n which added to its sum of digits gives 201301131212000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201301131212003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2302040279 + ... + 2302127721.
It is an arithmetic number, because the mean of its divisors is an integer number (2582871881499).
Almost surely, 2201301131212000 is an apocalyptic number.
201301131212000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 201301131212000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (247955700623904).
201301131212000 is an abundant number, since it is smaller than the sum of its proper divisors (294610270035808).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201301131212000 is an equidigital number, since it uses as much as digits as its factorization.
201301131212000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88990 (or 88972 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 201301131212000 its reverse (212131103102), we get a palindrome (201513262315102).
The spelling of 201301131212000 in words is "two hundred one trillion, three hundred one billion, one hundred thirty-one million, two hundred twelve thousand".
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