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201301241213 is a prime number
BaseRepresentation
bin1011101101111001111…
…1010010110101111101
3201020121000210120212102
42323132133102311331
511244231104204323
6232250532114445
720354301214112
oct2733637226575
9636530716772
10201301241213
117840a336a66
123301b465a25
1315ca0aa00a7
149a58c46909
15538280c328
hex2ede7d2d7d

201301241213 has 2 divisors, whose sum is σ = 201301241214. Its totient is φ = 201301241212.

The previous prime is 201301241203. The next prime is 201301241233. The reversal of 201301241213 is 312142103102.

It is an a-pointer prime, because the next prime (201301241233) can be obtained adding 201301241213 to its sum of digits (20).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132512016484 + 68789224729 = 364022^2 + 262277^2 .

It is a cyclic number.

It is not a de Polignac number, because 201301241213 - 28 = 201301240957 is a prime.

It is a super-2 number, since 2×2013012412132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201301241203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100650620606 + 100650620607.

It is an arithmetic number, because the mean of its divisors is an integer number (100650620607).

Almost surely, 2201301241213 is an apocalyptic number.

It is an amenable number.

201301241213 is a deficient number, since it is larger than the sum of its proper divisors (1).

201301241213 is an equidigital number, since it uses as much as digits as its factorization.

201301241213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 201301241213 its reverse (312142103102), we get a palindrome (513443344315).

The spelling of 201301241213 in words is "two hundred one billion, three hundred one million, two hundred forty-one thousand, two hundred thirteen".