Base | Representation |
---|---|
bin | 11101010010110000111… |
… | …001000101111111100100 |
3 | 21010102221022001212101211 |
4 | 131102300321011333210 |
5 | 230440122141420200 |
6 | 4140433135001204 |
7 | 265302216341614 |
oct | 35226071057744 |
9 | 7112838055354 |
10 | 2013012451300 |
11 | 706794060074 |
12 | 286175969204 |
13 | 117a983a55b6 |
14 | 6d604b3aa44 |
15 | 3756a58daba |
hex | 1d4b0e45fe4 |
2013012451300 has 36 divisors (see below), whose sum is σ = 4368305785536. Its totient is φ = 805192304800.
The previous prime is 2013012451297. The next prime is 2013012451309. The reversal of 2013012451300 is 31542103102.
It is a happy number.
It is not an unprimeable number, because it can be changed into a prime (2013012451309) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8676609 + ... + 8905591.
It is an arithmetic number, because the mean of its divisors is an integer number (121341827376).
Almost surely, 22013012451300 is an apocalyptic number.
2013012451300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2013012451300 is an abundant number, since it is smaller than the sum of its proper divisors (2355293334236).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2013012451300 is a wasteful number, since it uses less digits than its factorization.
2013012451300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 316908 (or 316901 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 2013012451300 its reverse (31542103102), we get a palindrome (2044554554402).
The spelling of 2013012451300 in words is "two trillion, thirteen billion, twelve million, four hundred fifty-one thousand, three hundred".
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