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2013013003 is a prime number
BaseRepresentation
bin111011111111100…
…0010010000001011
312012021211122201011
41313333002100023
513110312404003
6531425504351
7100612220401
oct16777022013
95167748634
102013013003
11943325511
124821a20b7
13261082471
141514c5471
15bbad346d
hex77fc240b

2013013003 has 2 divisors, whose sum is σ = 2013013004. Its totient is φ = 2013013002.

The previous prime is 2013013001. The next prime is 2013013021. The reversal of 2013013003 is 3003103102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2013013003 - 21 = 2013013001 is a prime.

Together with 2013013001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2013013001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006506501 + 1006506502.

It is an arithmetic number, because the mean of its divisors is an integer number (1006506502).

Almost surely, 22013013003 is an apocalyptic number.

2013013003 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013013003 is an equidigital number, since it uses as much as digits as its factorization.

2013013003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 13.

The square root of 2013013003 is about 44866.6134558872. The cubic root of 2013013003 is about 1262.6477041580.

Adding to 2013013003 its reverse (3003103102), we get a palindrome (5016116105).

Subtracting 2013013003 from its reverse (3003103102), we obtain a palindrome (990090099).

It can be divided in two parts, 201301 and 3003, that added together give a square (204304 = 4522).

The spelling of 2013013003 in words is "two billion, thirteen million, thirteen thousand, three".