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20130131423 is a prime number
BaseRepresentation
bin10010101111110110…
…010110110111011111
31220221220101122000002
4102233312112313133
5312211303201143
613125254324515
71311562202543
oct225766266737
956856348002
1020130131423
11859aa30756
123a9965973b
131b8a63b18c
14d8d6bba23
157cc3c35b8
hex4afd96ddf

20130131423 has 2 divisors, whose sum is σ = 20130131424. Its totient is φ = 20130131422.

The previous prime is 20130131401. The next prime is 20130131431. The reversal of 20130131423 is 32413103102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20130131423 - 28 = 20130131167 is a prime.

It is a super-2 number, since 2×201301314232 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20130131395 and 20130131404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130139423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065065711 + 10065065712.

It is an arithmetic number, because the mean of its divisors is an integer number (10065065712).

Almost surely, 220130131423 is an apocalyptic number.

20130131423 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130131423 is an equidigital number, since it uses as much as digits as its factorization.

20130131423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 20130131423 its reverse (32413103102), we get a palindrome (52543234525).

The spelling of 20130131423 in words is "twenty billion, one hundred thirty million, one hundred thirty-one thousand, four hundred twenty-three".