Base | Representation |
---|---|
bin | 10010101111110110… |
… | …010110110111100111 |
3 | 1220221220101122000101 |
4 | 102233312112313213 |
5 | 312211303201211 |
6 | 13125254324531 |
7 | 1311562202554 |
oct | 225766266747 |
9 | 56856348011 |
10 | 20130131431 |
11 | 859aa30763 |
12 | 3a99659747 |
13 | 1b8a63b197 |
14 | d8d6bba2b |
15 | 7cc3c35c1 |
hex | 4afd96de7 |
20130131431 has 2 divisors, whose sum is σ = 20130131432. Its totient is φ = 20130131430.
The previous prime is 20130131423. The next prime is 20130131519. The reversal of 20130131431 is 13413103102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20130131431 - 23 = 20130131423 is a prime.
It is a super-2 number, since 2×201301314312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20130131399 and 20130131408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20130131401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065065715 + 10065065716.
It is an arithmetic number, because the mean of its divisors is an integer number (10065065716).
Almost surely, 220130131431 is an apocalyptic number.
20130131431 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130131431 is an equidigital number, since it uses as much as digits as its factorization.
20130131431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 20130131431 its reverse (13413103102), we get a palindrome (33543234533).
The spelling of 20130131431 in words is "twenty billion, one hundred thirty million, one hundred thirty-one thousand, four hundred thirty-one".
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