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20130202021 is a prime number
BaseRepresentation
bin10010101111110110…
…101000000110100101
31220221220112012211211
4102233312220012211
5312211312431041
613125300031421
71311562615426
oct225766500645
956856465754
1020130202021
11859aa797a6
123a99692571
131b8a664357
14d8d6d964d
157cc3d9481
hex4afda81a5

20130202021 has 2 divisors, whose sum is σ = 20130202022. Its totient is φ = 20130202020.

The previous prime is 20130202009. The next prime is 20130202033. The reversal of 20130202021 is 12020203102.

It is a balanced prime because it is at equal distance from previous prime (20130202009) and next prime (20130202033).

It can be written as a sum of positive squares in only one way, i.e., 19720584900 + 409617121 = 140430^2 + 20239^2 .

It is a cyclic number.

It is not a de Polignac number, because 20130202021 - 213 = 20130193829 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20130201992 and 20130202010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130202091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065101010 + 10065101011.

It is an arithmetic number, because the mean of its divisors is an integer number (10065101011).

Almost surely, 220130202021 is an apocalyptic number.

It is an amenable number.

20130202021 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130202021 is an equidigital number, since it uses as much as digits as its factorization.

20130202021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 20130202021 its reverse (12020203102), we get a palindrome (32150405123).

The spelling of 20130202021 in words is "twenty billion, one hundred thirty million, two hundred two thousand, twenty-one".