Base | Representation |
---|---|
bin | 11101010010110010101… |
… | …110110100110110110111 |
3 | 21010110000110010212012121 |
4 | 131102302232310312313 |
5 | 230440203042022403 |
6 | 4140440200300411 |
7 | 265303042562623 |
oct | 35226256646667 |
9 | 7113013125177 |
10 | 2013043314103 |
11 | 7067aa51a818 |
12 | 286184171707 |
13 | 117aa18c0203 |
14 | 6d608c92183 |
15 | 3756d1383bd |
hex | 1d4b2bb4db7 |
2013043314103 has 2 divisors, whose sum is σ = 2013043314104. Its totient is φ = 2013043314102.
The previous prime is 2013043314101. The next prime is 2013043314143. The reversal of 2013043314103 is 3014133403102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013043314103 - 21 = 2013043314101 is a prime.
Together with 2013043314101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013043314101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006521657051 + 1006521657052.
It is an arithmetic number, because the mean of its divisors is an integer number (1006521657052).
Almost surely, 22013043314103 is an apocalyptic number.
2013043314103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013043314103 is an equidigital number, since it uses as much as digits as its factorization.
2013043314103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 2013043314103 its reverse (3014133403102), we get a palindrome (5027176717205).
The spelling of 2013043314103 in words is "two trillion, thirteen billion, forty-three million, three hundred fourteen thousand, one hundred three".
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