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2013043314101 is a prime number
BaseRepresentation
bin11101010010110010101…
…110110100110110110101
321010110000110010212012112
4131102302232310312311
5230440203042022401
64140440200300405
7265303042562621
oct35226256646665
97113013125175
102013043314101
117067aa51a816
12286184171705
13117aa18c0201
146d608c92181
153756d1383bb
hex1d4b2bb4db5

2013043314101 has 2 divisors, whose sum is σ = 2013043314102. Its totient is φ = 2013043314100.

The previous prime is 2013043314083. The next prime is 2013043314103. The reversal of 2013043314101 is 1014133403102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1652291722225 + 360751591876 = 1285415^2 + 600626^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013043314101 is a prime.

Together with 2013043314103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013043314103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006521657050 + 1006521657051.

It is an arithmetic number, because the mean of its divisors is an integer number (1006521657051).

Almost surely, 22013043314101 is an apocalyptic number.

It is an amenable number.

2013043314101 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013043314101 is an equidigital number, since it uses as much as digits as its factorization.

2013043314101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 2013043314101 its reverse (1014133403102), we get a palindrome (3027176717203).

The spelling of 2013043314101 in words is "two trillion, thirteen billion, forty-three million, three hundred fourteen thousand, one hundred one".