2013101104013 has 4 divisors (see below), whose sum is σ = 2033854723740. Its totient is φ = 1992347484288.

The previous prime is 2013101104009. The next prime is 2013101104019. The reversal of 2013101104013 is 3104011013102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 336379120324 + 1676721983689 = 579982^2 + 1294883^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013101104013 - 2² = 2013101104009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2013101103982 and 2013101104000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013101104019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10376809718 + ... + 10376809911.

It is an arithmetic number, because the mean of its divisors is an integer number (508463680935).

Almost surely, 2^{2013101104013} is an apocalyptic number.

It is an amenable number.

2013101104013 is a deficient number, since it is larger than the sum of its proper divisors (20753619727).

2013101104013 is an equidigital number, since it uses as much as digits as its factorization.

2013101104013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20753619726.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 2013101104013 its reverse (3104011013102), we get a palindrome (5117112117115).

The spelling of 2013101104013 in words is "two trillion, thirteen billion, one hundred one million, one hundred four thousand, thirteen".