Base | Representation |
---|---|
bin | 1011101101111100000… |
… | …1011110000011000000 |
3 | 201020121122122202000100 |
4 | 2323133001132003000 |
5 | 11244240402400000 |
6 | 232251452122400 |
7 | 20354440316040 |
oct | 2733701360300 |
9 | 636548582010 |
10 | 201310200000 |
11 | 784143a5918 |
12 | 33022466400 |
13 | 15ca28b8a50 |
14 | 9a5a0d9720 |
15 | 53834cba00 |
hex | 2edf05e0c0 |
201310200000 has 1008 divisors, whose sum is σ = 888387514560. Its totient is φ = 42439680000.
The previous prime is 201310199963. The next prime is 201310200043. The reversal of 201310200000 is 2013102.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (1008).
It is a super-4 number, since 4×2013102000004 (a number of 46 digits) contains 4444 as substring.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 163799386 + ... + 163800614.
It is an arithmetic number, because the mean of its divisors is an integer number (881336820).
Almost surely, 2201310200000 is an apocalyptic number.
201310200000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 201310200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (444193757280).
201310200000 is an abundant number, since it is smaller than the sum of its proper divisors (687077314560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201310200000 is a wasteful number, since it uses less digits than its factorization.
201310200000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1292 (or 1259 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 9.
Adding to 201310200000 its reverse (2013102), we get a palindrome (201312213102).
201310200000 divided by its reverse (2013102) gives a 5-th power (100000 = 105).
The spelling of 201310200000 in words is "two hundred one billion, three hundred ten million, two hundred thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •