Base | Representation |
---|---|
bin | 1011101101111100010… |
… | …0100001111010111100 |
3 | 201020121201011111120011 |
4 | 2323133010201322330 |
5 | 11244241104033200 |
6 | 232251521233004 |
7 | 20354450200102 |
oct | 2733704417274 |
9 | 636551144504 |
10 | 201311002300 |
11 | 784148a3681 |
12 | 33022792764 |
13 | 15ca2b09c95 |
14 | 9a5a267c72 |
15 | 53835d95ba |
hex | 2edf121ebc |
201311002300 has 144 divisors (see below), whose sum is σ = 479101835520. Its totient is φ = 73204992000.
The previous prime is 201311002289. The next prime is 201311002303. The reversal of 201311002300 is 3200113102.
It is a super-2 number, since 2×2013110023002 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201311002303) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3296040 + ... + 3356560.
It is an arithmetic number, because the mean of its divisors is an integer number (3327096080).
Almost surely, 2201311002300 is an apocalyptic number.
201311002300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 201311002300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (239550917760).
201311002300 is an abundant number, since it is smaller than the sum of its proper divisors (277790833220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201311002300 is a wasteful number, since it uses less digits than its factorization.
201311002300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60632 (or 60625 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 201311002300 its reverse (3200113102), we get a palindrome (204511115402).
The spelling of 201311002300 in words is "two hundred one billion, three hundred eleven million, two thousand, three hundred".
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