| Base | Representation |
|---|---|
| bin | 1011101101111100010… |
| … | …0100010101000010000 |
| 3 | 201020121201011122112120 |
| 4 | 2323133010202220100 |
| 5 | 11244241104131300 |
| 6 | 232251521254240 |
| 7 | 20354450211414 |
| oct | 2733704425020 |
| 9 | 636551148476 |
| 10 | 201311005200 |
| 11 | 784148a5878 |
| 12 | 33022794380 |
| 13 | 15ca2b0b3b6 |
| 14 | 9a5a268d44 |
| 15 | 53835da3a0 |
| hex | 2edf122a10 |
201311005200 has 240 divisors, whose sum is σ = 696110267520. Its totient is φ = 49578045440.
The previous prime is 201311005097. The next prime is 201311005213. The reversal of 201311005200 is 2500113102.
It is a tau number, because it is divible by the number of its divisors (240).
It is a super-2 number, since 2×2013110052002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 201311005200.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 674644 + ... + 926156.
It is an arithmetic number, because the mean of its divisors is an integer number (2900459448).
Almost surely, 2201311005200 is an apocalyptic number.
201311005200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 201311005200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (348055133760).
201311005200 is an abundant number, since it is smaller than the sum of its proper divisors (494799262320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201311005200 is a wasteful number, since it uses less digits than its factorization.
201311005200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 251586 (or 251575 counting only the distinct ones).
The product of its (nonzero) digits is 60, while the sum is 15.
Adding to 201311005200 its reverse (2500113102), we get a palindrome (203811118302).
The spelling of 201311005200 in words is "two hundred one billion, three hundred eleven million, five thousand, two hundred".
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