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2013110111 is a prime number
BaseRepresentation
bin111011111111101…
…1001111101011111
312012022000120220202
41313333121331133
513110324010421
6531431534115
7100613103455
oct16777317537
95168016822
102013110111
11943391471
1248222a33b
132610b771c
1415150c9d5
15bbb0210b
hex77fd9f5f

2013110111 has 2 divisors, whose sum is σ = 2013110112. Its totient is φ = 2013110110.

The previous prime is 2013110107. The next prime is 2013110129. The reversal of 2013110111 is 1110113102.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2013110111 - 22 = 2013110107 is a prime.

It is a super-2 number, since 2×20131101112 = 8105224638020864642, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2013110092 and 2013110101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013110191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006555055 + 1006555056.

It is an arithmetic number, because the mean of its divisors is an integer number (1006555056).

Almost surely, 22013110111 is an apocalyptic number.

2013110111 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013110111 is an equidigital number, since it uses as much as digits as its factorization.

2013110111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

The square root of 2013110111 is about 44867.6956283694. The cubic root of 2013110111 is about 1262.6680072594.

Adding to 2013110111 its reverse (1110113102), we get a palindrome (3123223213).

The spelling of 2013110111 in words is "two billion, thirteen million, one hundred ten thousand, one hundred eleven".