Base | Representation |
---|---|
bin | 10010101111111010… |
… | …001011011010101100 |
3 | 1220221222021112001020 |
4 | 102233322023122230 |
5 | 312212032224400 |
6 | 13125332014140 |
7 | 1311603544101 |
oct | 225772133254 |
9 | 56858245036 |
10 | 20131133100 |
11 | 85a0555291 |
12 | 3a99a61350 |
13 | 1b8a8cc0a0 |
14 | d8d89caa8 |
15 | 7cc5202a0 |
hex | 4afe8b6ac |
20131133100 has 432 divisors, whose sum is σ = 68092079328. Its totient is φ = 4562288640.
The previous prime is 20131133089. The next prime is 20131133119. The reversal of 20131133100 is 133113102.
It is a super-2 number, since 2×201311331002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 20131133100.
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 59736132 + ... + 59736468.
It is an arithmetic number, because the mean of its divisors is an integer number (157620554).
Almost surely, 220131133100 is an apocalyptic number.
20131133100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 20131133100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (34046039664).
20131133100 is an abundant number, since it is smaller than the sum of its proper divisors (47960946228).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20131133100 is a wasteful number, since it uses less digits than its factorization.
20131133100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 454 (or 430 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 20131133100 its reverse (133113102), we get a palindrome (20264246202).
The spelling of 20131133100 in words is "twenty billion, one hundred thirty-one million, one hundred thirty-three thousand, one hundred".
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