Base | Representation |
---|---|
bin | 11101010010111000100… |
… | …011111100001101000111 |
3 | 21010110021021012010001002 |
4 | 131102320203330031013 |
5 | 230440403111431121 |
6 | 4140454012523515 |
7 | 265305341133461 |
oct | 35227043741507 |
9 | 7113237163032 |
10 | 2013141123911 |
11 | 70684a755775 |
12 | 2861b0a8059b |
13 | 117ab8c47b38 |
14 | 6d617c73131 |
15 | 37576a08e0b |
hex | 1d4b88fc347 |
2013141123911 has 2 divisors, whose sum is σ = 2013141123912. Its totient is φ = 2013141123910.
The previous prime is 2013141123883. The next prime is 2013141123913. The reversal of 2013141123911 is 1193211413102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013141123911 is a prime.
Together with 2013141123913, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013141123913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006570561955 + 1006570561956.
It is an arithmetic number, because the mean of its divisors is an integer number (1006570561956).
Almost surely, 22013141123911 is an apocalyptic number.
2013141123911 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013141123911 is an equidigital number, since it uses as much as digits as its factorization.
2013141123911 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 29.
The spelling of 2013141123911 in words is "two trillion, thirteen billion, one hundred forty-one million, one hundred twenty-three thousand, nine hundred eleven".
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