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2013143201303 = 13191467808793
BaseRepresentation
bin11101010010111000101…
…011110111011000010111
321010110021102002122200112
4131102320223313120113
5230440404124420203
64140454125233235
7265305364605143
oct35227053673027
97113242078615
102013143201303
11706850944523
122861b170281b
13117ab94c4570
146d618254223
1537576cb96d8
hex1d4b8af7617

2013143201303 has 8 divisors (see below), whose sum is σ = 2168014374288. Its totient is φ = 1858274028864.

The previous prime is 2013143201299. The next prime is 2013143201317. The reversal of 2013143201303 is 3031023413102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013143201303 - 22 = 2013143201299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013143401303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2084675 + ... + 2893467.

It is an arithmetic number, because the mean of its divisors is an integer number (271001796786).

Almost surely, 22013143201303 is an apocalyptic number.

2013143201303 is a deficient number, since it is larger than the sum of its proper divisors (154871172985).

2013143201303 is a wasteful number, since it uses less digits than its factorization.

2013143201303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1000273.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 2013143201303 its reverse (3031023413102), we get a palindrome (5044166614405).

The spelling of 2013143201303 in words is "two trillion, thirteen billion, one hundred forty-three million, two hundred one thousand, three hundred three".

Divisors: 1 13 191467 808793 2489071 10514309 154857169331 2013143201303