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201321101011 = 541937150969
BaseRepresentation
bin1011101101111110101…
…1000011011011010011
3201020122102011120101111
42323133223003123103
511244301200213021
6232252521514151
720354632060312
oct2733753033323
9636572146344
10201321101011
117841a570a18
1233026042957
1315ca4c34754
149a5b736279
1553844318e1
hex2edfac36d3

201321101011 has 4 divisors (see below), whose sum is σ = 201358257400. Its totient is φ = 201283944624.

The previous prime is 201321100991. The next prime is 201321101029. The reversal of 201321101011 is 110101123102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201321101011 - 25 = 201321100979 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201321100982 and 201321101000.

It is not an unprimeable number, because it can be changed into a prime (201321101041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18570066 + ... + 18580903.

It is an arithmetic number, because the mean of its divisors is an integer number (50339564350).

Almost surely, 2201321101011 is an apocalyptic number.

201321101011 is a deficient number, since it is larger than the sum of its proper divisors (37156389).

201321101011 is an equidigital number, since it uses as much as digits as its factorization.

201321101011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37156388.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 201321101011 its reverse (110101123102), we get a palindrome (311422224113).

The spelling of 201321101011 in words is "two hundred one billion, three hundred twenty-one million, one hundred one thousand, eleven".

Divisors: 1 5419 37150969 201321101011