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201328214953 is a prime number
BaseRepresentation
bin1011101110000000011…
…0001100001110101001
3201020122220112222212211
42323200012030032221
511244310010334303
6232253334205121
720355046406545
oct2734006141651
9636586488784
10201328214953
117842358a808
12330284b37a1
1315ca6555798
149a5c668a25
155384d8966d
hex2ee018c3a9

201328214953 has 2 divisors, whose sum is σ = 201328214954. Its totient is φ = 201328214952.

The previous prime is 201328214951. The next prime is 201328214981. The reversal of 201328214953 is 359412823102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 191150835264 + 10177379689 = 437208^2 + 100883^2 .

It is a cyclic number.

It is not a de Polignac number, because 201328214953 - 21 = 201328214951 is a prime.

It is a super-2 number, since 2×2013282149532 (a number of 23 digits) contains 22 as substring.

Together with 201328214951, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (201328214951) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100664107476 + 100664107477.

It is an arithmetic number, because the mean of its divisors is an integer number (100664107477).

Almost surely, 2201328214953 is an apocalyptic number.

It is an amenable number.

201328214953 is a deficient number, since it is larger than the sum of its proper divisors (1).

201328214953 is an equidigital number, since it uses as much as digits as its factorization.

201328214953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 40.

The spelling of 201328214953 in words is "two hundred one billion, three hundred twenty-eight million, two hundred fourteen thousand, nine hundred fifty-three".