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201328214981 is a prime number
BaseRepresentation
bin1011101110000000011…
…0001100001111000101
3201020122220112222220212
42323200012030033011
511244310010334411
6232253334205205
720355046406615
oct2734006141705
9636586488825
10201328214981
117842358a833
12330284b3805
1315ca65557ba
149a5c668a45
155384d8968b
hex2ee018c3c5

201328214981 has 2 divisors, whose sum is σ = 201328214982. Its totient is φ = 201328214980.

The previous prime is 201328214953. The next prime is 201328215007. The reversal of 201328214981 is 189412823102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 165136576900 + 36191638081 = 406370^2 + 190241^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201328214981 is a prime.

It is a super-2 number, since 2×2013282149812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201328214921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100664107490 + 100664107491.

It is an arithmetic number, because the mean of its divisors is an integer number (100664107491).

Almost surely, 2201328214981 is an apocalyptic number.

It is an amenable number.

201328214981 is a deficient number, since it is larger than the sum of its proper divisors (1).

201328214981 is an equidigital number, since it uses as much as digits as its factorization.

201328214981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 41.

The spelling of 201328214981 in words is "two hundred one billion, three hundred twenty-eight million, two hundred fourteen thousand, nine hundred eighty-one".