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201331104000 = 2835313161323
BaseRepresentation
bin1011101110000001000…
…1001101100100000000
3201020200002222202220120
42323200101031210000
511244311230312000
6232253520140240
720355113101455
oct2734021154400
9636602882816
10201331104000
1178425183354
1233029467680
1315ca7027790
149a5cbbb82c
15538525a6a0
hex2ee044d900

201331104000 has 288 divisors, whose sum is σ = 720165823104. Its totient is φ = 49558118400.

The previous prime is 201331103983. The next prime is 201331104031. The reversal of 201331104000 is 401133102.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1167339 + ... + 1328661.

Almost surely, 2201331104000 is an apocalyptic number.

201331104000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201331104000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (360082911552).

201331104000 is an abundant number, since it is smaller than the sum of its proper divisors (518834719104).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201331104000 is a wasteful number, since it uses less digits than its factorization.

201331104000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161370 (or 161346 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 201331104000 its reverse (401133102), we get a palindrome (201732237102).

The spelling of 201331104000 in words is "two hundred one billion, three hundred thirty-one million, one hundred four thousand".