Base | Representation |
---|---|
bin | 11101010011000011010… |
… | …010001001110001111111 |
3 | 21010110201210200021210001 |
4 | 131103003102021301333 |
5 | 230441240134312203 |
6 | 4140523520255131 |
7 | 265312654136551 |
oct | 35230322116177 |
9 | 7113653607701 |
10 | 2013321010303 |
11 | 706932250009 |
12 | 2862411714a7 |
13 | 117b172ac0a5 |
14 | 6d633adb4d1 |
15 | 375876dd91d |
hex | 1d4c3489c7f |
2013321010303 has 2 divisors, whose sum is σ = 2013321010304. Its totient is φ = 2013321010302.
The previous prime is 2013321010301. The next prime is 2013321010343. The reversal of 2013321010303 is 3030101233102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013321010303 - 21 = 2013321010301 is a prime.
It is a super-2 number, since 2×20133210103032 (a number of 25 digits) contains 22 as substring.
Together with 2013321010301, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013321010301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006660505151 + 1006660505152.
It is an arithmetic number, because the mean of its divisors is an integer number (1006660505152).
Almost surely, 22013321010303 is an apocalyptic number.
2013321010303 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013321010303 is an equidigital number, since it uses as much as digits as its factorization.
2013321010303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 2013321010303 its reverse (3030101233102), we get a palindrome (5043422243405).
The spelling of 2013321010303 in words is "two trillion, thirteen billion, three hundred twenty-one million, ten thousand, three hundred three".
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