Base | Representation |
---|---|
bin | 11101010011000011011… |
… | …110000100001010001000 |
3 | 21010110202000112221022111 |
4 | 131103003132010022020 |
5 | 230441241434224000 |
6 | 4140524111232104 |
7 | 265313022523615 |
oct | 35230336041210 |
9 | 7113660487274 |
10 | 2013324133000 |
11 | 706933a93154 |
12 | 286242218634 |
13 | 117b17b3353b |
14 | 6d6342b150c |
15 | 37587b08cba |
hex | 1d4c3784288 |
2013324133000 has 64 divisors (see below), whose sum is σ = 4712872993920. Its totient is φ = 805039992000.
The previous prime is 2013324132943. The next prime is 2013324133027. The reversal of 2013324133000 is 3314233102.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2430319 + ... + 3151681.
It is an arithmetic number, because the mean of its divisors is an integer number (73638640530).
Almost surely, 22013324133000 is an apocalyptic number.
2013324133000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2013324133000 is an abundant number, since it is smaller than the sum of its proper divisors (2699548860920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2013324133000 is a wasteful number, since it uses less digits than its factorization.
2013324133000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 724175 (or 724161 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 2013324133000 its reverse (3314233102), we get a palindrome (2016638366102).
The spelling of 2013324133000 in words is "two trillion, thirteen billion, three hundred twenty-four million, one hundred thirty-three thousand".
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