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2013341335 = 51283313849
BaseRepresentation
bin111100000000001…
…0010011010010111
312012022110100002121
41320000102122113
513110403410320
6531440520411
7100615055545
oct17000223227
95168410077
102013341335
1194352a165
12482320107
13261168a45
1415156cd95
15bbb4a8aa
hex78012697

2013341335 has 8 divisors (see below), whose sum is σ = 2417900400. Its totient is φ = 1609412544.

The previous prime is 2013341333. The next prime is 2013341339. The reversal of 2013341335 is 5331433102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013341335 - 21 = 2013341333 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013341333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 150510 + ... + 163339.

It is an arithmetic number, because the mean of its divisors is an integer number (302237550).

Almost surely, 22013341335 is an apocalyptic number.

2013341335 is a deficient number, since it is larger than the sum of its proper divisors (404559065).

2013341335 is a wasteful number, since it uses less digits than its factorization.

2013341335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 315137.

The product of its (nonzero) digits is 3240, while the sum is 25.

The square root of 2013341335 is about 44870.2722857796. The cubic root of 2013341335 is about 1262.7163483757.

Adding to 2013341335 its reverse (5331433102), we get a palindrome (7344774437).

The spelling of 2013341335 in words is "two billion, thirteen million, three hundred forty-one thousand, three hundred thirty-five".

Divisors: 1 5 1283 6415 313849 1569245 402668267 2013341335