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201340200031 is a prime number
BaseRepresentation
bin1011101110000011001…
…1111010010001011111
3201020200202002220022121
42323200303322101133
511244321042400111
6232254443123411
720355253314505
oct2734063722137
9636622086277
10201340200031
117842a326333
1233030513567
1315ca8b90a49
149a600a8675
155385e55871
hex2ee0cfa45f

201340200031 has 2 divisors, whose sum is σ = 201340200032. Its totient is φ = 201340200030.

The previous prime is 201340200029. The next prime is 201340200059. The reversal of 201340200031 is 130002043102.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201340200031 - 21 = 201340200029 is a prime.

It is a super-2 number, since 2×2013402000312 (a number of 23 digits) contains 22 as substring.

Together with 201340200029, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 201340199978 and 201340200014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201340200011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670100015 + 100670100016.

It is an arithmetic number, because the mean of its divisors is an integer number (100670100016).

Almost surely, 2201340200031 is an apocalyptic number.

201340200031 is a deficient number, since it is larger than the sum of its proper divisors (1).

201340200031 is an equidigital number, since it uses as much as digits as its factorization.

201340200031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 201340200031 its reverse (130002043102), we get a palindrome (331342243133).

The spelling of 201340200031 in words is "two hundred one billion, three hundred forty million, two hundred thousand, thirty-one".