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2013410414143 = 5689353912887
BaseRepresentation
bin11101010011001000100…
…111001100111000111111
321010110222000220110210101
4131103020213030320333
5230441431031223033
64140540432421531
7265315121100262
oct35231047147077
97113860813711
102013410414143
11706978764487
122862670a78a7
13117b2c98287b
146d641930cd9
153759049d97d
hex1d4c89cce3f

2013410414143 has 4 divisors (see below), whose sum is σ = 2013764332720. Its totient is φ = 2013056495568.

The previous prime is 2013410414131. The next prime is 2013410414153. The reversal of 2013410414143 is 3414140143102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013410414143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013410414153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176950755 + ... + 176962132.

It is an arithmetic number, because the mean of its divisors is an integer number (503441083180).

Almost surely, 22013410414143 is an apocalyptic number.

2013410414143 is a deficient number, since it is larger than the sum of its proper divisors (353918577).

2013410414143 is an equidigital number, since it uses as much as digits as its factorization.

2013410414143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 353918576.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 2013410414143 its reverse (3414140143102), we get a palindrome (5427550557245).

The spelling of 2013410414143 in words is "two trillion, thirteen billion, four hundred ten million, four hundred fourteen thousand, one hundred forty-three".

Divisors: 1 5689 353912887 2013410414143