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2013424001 is a prime number
BaseRepresentation
bin111100000000010…
…0110100110000001
312012022121112111022
41320000212212001
513110414032001
6531442355225
7100615551551
oct17000464601
95168545438
102013424001
11943586286
1248235bb15
13261197564
14151591161
15bbb6511b
hex78026981

2013424001 has 2 divisors, whose sum is σ = 2013424002. Its totient is φ = 2013424000.

The previous prime is 2013423983. The next prime is 2013424003. The reversal of 2013424001 is 1004243102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1526074225 + 487349776 = 39065^2 + 22076^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013424001 - 222 = 2009229697 is a prime.

Together with 2013424003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2013424003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006712000 + 1006712001.

It is an arithmetic number, because the mean of its divisors is an integer number (1006712001).

Almost surely, 22013424001 is an apocalyptic number.

It is an amenable number.

2013424001 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013424001 is an equidigital number, since it uses as much as digits as its factorization.

2013424001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 17.

The square root of 2013424001 is about 44871.1934430097. The cubic root of 2013424001 is about 1262.7336301417.

Adding to 2013424001 its reverse (1004243102), we get a palindrome (3017667103).

The spelling of 2013424001 in words is "two billion, thirteen million, four hundred twenty-four thousand, one".