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201342441317 is a prime number
BaseRepresentation
bin1011101110000011110…
…0011101011101100101
3201020200220022202210012
42323200330131131211
511244322131110232
6232255003140005
720355311341043
oct2734074353545
9636626282705
10201342441317
1178430617236
1233031214605
1315ca9496c54
149a604cd393
1553862499b2
hex2ee0f1d765

201342441317 has 2 divisors, whose sum is σ = 201342441318. Its totient is φ = 201342441316.

The previous prime is 201342441281. The next prime is 201342441319. The reversal of 201342441317 is 713144243102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 201139692196 + 202749121 = 448486^2 + 14239^2 .

It is a cyclic number.

It is not a de Polignac number, because 201342441317 - 216 = 201342375781 is a prime.

Together with 201342441319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201342441319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100671220658 + 100671220659.

It is an arithmetic number, because the mean of its divisors is an integer number (100671220659).

Almost surely, 2201342441317 is an apocalyptic number.

It is an amenable number.

201342441317 is a deficient number, since it is larger than the sum of its proper divisors (1).

201342441317 is an equidigital number, since it uses as much as digits as its factorization.

201342441317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 32.

Adding to 201342441317 its reverse (713144243102), we get a palindrome (914486684419).

The spelling of 201342441317 in words is "two hundred one billion, three hundred forty-two million, four hundred forty-one thousand, three hundred seventeen".