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2013433040440 = 23550335826011
BaseRepresentation
bin11101010011001001111…
…101100000111000111000
321010111000121111000020101
4131103021331200320320
5230442002324243230
64140543001405144
7265315514315203
oct35231175407070
97114017430211
102013433040440
1170698a5089a8
122862727997b4
13117b34575503
146d64494093a
153759246caca
hex1d4c9f60e38

2013433040440 has 16 divisors (see below), whose sum is σ = 4530224341080. Its totient is φ = 805373216160.

The previous prime is 2013433040371. The next prime is 2013433040447. The reversal of 2013433040440 is 440403343102.

It is a junction number, because it is equal to n+sod(n) for n = 2013433040399 and 2013433040408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013433040447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25167912966 + ... + 25167913045.

Almost surely, 22013433040440 is an apocalyptic number.

2013433040440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

2013433040440 is an abundant number, since it is smaller than the sum of its proper divisors (2516791300640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013433040440 is a wasteful number, since it uses less digits than its factorization.

2013433040440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50335826022 (or 50335826018 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 2013433040440 its reverse (440403343102), we get a palindrome (2453836383542).

The spelling of 2013433040440 in words is "two trillion, thirteen billion, four hundred thirty-three million, forty thousand, four hundred forty".

Divisors: 1 2 4 5 8 10 20 40 50335826011 100671652022 201343304044 251679130055 402686608088 503358260110 1006716520220 2013433040440