Base | Representation |
---|---|
bin | 11101010011010100100… |
… | …101101011101100101011 |
3 | 21010111111000222200212101 |
4 | 131103110211223230223 |
5 | 230442334000431020 |
6 | 4141012411154231 |
7 | 265323111002524 |
oct | 35232445535453 |
9 | 7114430880771 |
10 | 2013611342635 |
11 | 706a71120a92 |
12 | 286302445977 |
13 | 117b624a3679 |
14 | 6d6604b584b |
15 | 375a2e3d00a |
hex | 1d4d496bb2b |
2013611342635 has 8 divisors (see below), whose sum is σ = 2521391594400. Its totient is φ = 1540850418624.
The previous prime is 2013611342591. The next prime is 2013611342647. The reversal of 2013611342635 is 5362431163102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2013611342635 - 233 = 2005021408043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2013611342594 and 2013611342603.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8754831810 + ... + 8754832039.
It is an arithmetic number, because the mean of its divisors is an integer number (315173949300).
Almost surely, 22013611342635 is an apocalyptic number.
2013611342635 is a deficient number, since it is larger than the sum of its proper divisors (507780251765).
2013611342635 is a wasteful number, since it uses less digits than its factorization.
2013611342635 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17509663877.
The product of its (nonzero) digits is 77760, while the sum is 37.
The spelling of 2013611342635 in words is "two trillion, thirteen billion, six hundred eleven million, three hundred forty-two thousand, six hundred thirty-five".
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