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2014013 is a prime number
BaseRepresentation
bin111101011101100111101
310210022201002
413223230331
51003422023
6111100045
723055521
oct7535475
93708632
102014013
111156181
12811625
13556931
143a5d81
1529bb28
hex1ebb3d

2014013 has 2 divisors, whose sum is σ = 2014014. Its totient is φ = 2014012.

The previous prime is 2014009. The next prime is 2014027. The reversal of 2014013 is 3104102.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1162084 + 851929 = 1078^2 + 923^2 .

It is a cyclic number.

It is not a de Polignac number, because 2014013 - 22 = 2014009 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2013985 and 2014003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2014213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007006 + 1007007.

It is an arithmetic number, because the mean of its divisors is an integer number (1007007).

22014013 is an apocalyptic number.

It is an amenable number.

2014013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014013 is an equidigital number, since it uses as much as digits as its factorization.

2014013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 11.

The square root of 2014013 is about 1419.1592581525. The cubic root of 2014013 is about 126.2856749818.

Adding to 2014013 its reverse (3104102), we get a palindrome (5118115).

The spelling of 2014013 in words is "two million, fourteen thousand, thirteen".