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20143104431 is a prime number
BaseRepresentation
bin10010110000100111…
…110110000110101111
31220222210210201121212
4102300213312012233
5312223113320211
613130440345035
71312110363662
oct226047660657
956883721555
1020143104431
1185a729154a
123aa1a7517b
131b90231008
14d912d76d9
157cd5d738b
hex4b09f61af

20143104431 has 2 divisors, whose sum is σ = 20143104432. Its totient is φ = 20143104430.

The previous prime is 20143104419. The next prime is 20143104433. The reversal of 20143104431 is 13440134102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20143104431 is a prime.

It is a super-2 number, since 2×201431044312 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 20143104433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 20143104397 and 20143104406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20143104433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10071552215 + 10071552216.

It is an arithmetic number, because the mean of its divisors is an integer number (10071552216).

Almost surely, 220143104431 is an apocalyptic number.

20143104431 is a deficient number, since it is larger than the sum of its proper divisors (1).

20143104431 is an equidigital number, since it uses as much as digits as its factorization.

20143104431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 20143104431 its reverse (13440134102), we get a palindrome (33583238533).

The spelling of 20143104431 in words is "twenty billion, one hundred forty-three million, one hundred four thousand, four hundred thirty-one".