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2015112023 is a prime number
BaseRepresentation
bin111100000011100…
…0010101101010111
312012102210022000122
41320013002231113
513111332041043
6531542502155
7100636112111
oct17007025527
95172708018
102015112023
11944529541
12482a3495b
132616389a2
141518b03b1
15bbd9a368
hex781c2b57

2015112023 has 2 divisors, whose sum is σ = 2015112024. Its totient is φ = 2015112022.

The previous prime is 2015112007. The next prime is 2015112037. The reversal of 2015112023 is 3202115102.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2015112023 - 24 = 2015112007 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2015111992 and 2015112010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2015112083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007556011 + 1007556012.

It is an arithmetic number, because the mean of its divisors is an integer number (1007556012).

Almost surely, 22015112023 is an apocalyptic number.

2015112023 is a deficient number, since it is larger than the sum of its proper divisors (1).

2015112023 is an equidigital number, since it uses as much as digits as its factorization.

2015112023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 2015112023 is about 44889.9991423480. Note that the first 3 decimals coincide. The cubic root of 2015112023 is about 1263.0864166960.

Adding to 2015112023 its reverse (3202115102), we get a palindrome (5217227125).

The spelling of 2015112023 in words is "two billion, fifteen million, one hundred twelve thousand, twenty-three".