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20151983 is a prime number
BaseRepresentation
bin100110011011…
…1111010101111
31101220211022202
41030313322233
520124330413
61555532115
7333201065
oct114677257
941824282
1020151983
1110414535
1268ba03b
134237667
142968035
151b80e58
hex1337eaf

20151983 has 2 divisors, whose sum is σ = 20151984. Its totient is φ = 20151982.

The previous prime is 20151973. The next prime is 20151991. The reversal of 20151983 is 38915102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20151983 - 220 = 19103407 is a prime.

It is a super-3 number, since 3×201519833 (a number of 23 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20151973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10075991 + 10075992.

It is an arithmetic number, because the mean of its divisors is an integer number (10075992).

Almost surely, 220151983 is an apocalyptic number.

20151983 is a deficient number, since it is larger than the sum of its proper divisors (1).

20151983 is an equidigital number, since it uses as much as digits as its factorization.

20151983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 29.

The square root of 20151983 is about 4489.0960114482. The cubic root of 20151983 is about 272.1276028664.

The spelling of 20151983 in words is "twenty million, one hundred fifty-one thousand, nine hundred eighty-three".