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20153147 = 78334687
BaseRepresentation
bin100110011100…
…0001100111011
31101220212220212
41030320030323
520124400042
61555541335
7333204350
oct114701473
941825825
1020153147
11104153a3
1268ba84b
134238051
142968627
151b81482
hex133833b

20153147 has 8 divisors (see below), whose sum is σ = 23310336. Its totient is φ = 17065512.

The previous prime is 20153141. The next prime is 20153153. The reversal of 20153147 is 74135102.

It is an interprime number because it is at equal distance from previous prime (20153141) and next prime (20153153).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20153147 is a prime.

It is a super-2 number, since 2×201531472 = 812298668007218, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (20153141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16763 + ... + 17924.

It is an arithmetic number, because the mean of its divisors is an integer number (2913792).

Almost surely, 220153147 is an apocalyptic number.

20153147 is a deficient number, since it is larger than the sum of its proper divisors (3157189).

20153147 is an equidigital number, since it uses as much as digits as its factorization.

20153147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34777.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 20153147 is about 4489.2256570594. The cubic root of 20153147 is about 272.1328422256.

Adding to 20153147 its reverse (74135102), we get a palindrome (94288249).

The spelling of 20153147 in words is "twenty million, one hundred fifty-three thousand, one hundred forty-seven".

Divisors: 1 7 83 581 34687 242809 2879021 20153147