Base | Representation |
---|---|
bin | 10010110001010010… |
… | …011000101100001101 |
3 | 1221000120210021220011 |
4 | 102301102120230031 |
5 | 312233442144031 |
6 | 13131515353221 |
7 | 1312304231155 |
oct | 226122305415 |
9 | 57016707804 |
10 | 20154256141 |
11 | 8602608a38 |
12 | 3aa5752811 |
13 | 1b92636b66 |
14 | d9299b765 |
15 | 7ce58b6b1 |
hex | 4b1498b0d |
20154256141 has 2 divisors, whose sum is σ = 20154256142. Its totient is φ = 20154256140.
The previous prime is 20154256139. The next prime is 20154256249. The reversal of 20154256141 is 14165245102.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18341284900 + 1812971241 = 135430^2 + 42579^2 .
It is a cyclic number.
It is not a de Polignac number, because 20154256141 - 21 = 20154256139 is a prime.
Together with 20154256139, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20151256141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077128070 + 10077128071.
It is an arithmetic number, because the mean of its divisors is an integer number (10077128071).
Almost surely, 220154256141 is an apocalyptic number.
It is an amenable number.
20154256141 is a deficient number, since it is larger than the sum of its proper divisors (1).
20154256141 is an equidigital number, since it uses as much as digits as its factorization.
20154256141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 31.
The spelling of 20154256141 in words is "twenty billion, one hundred fifty-four million, two hundred fifty-six thousand, one hundred forty-one".
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