Search a number
-
+
2020341311 is a prime number
BaseRepresentation
bin111100001101011…
…1111011000111111
312012210121222020222
41320122333120333
513114201410221
6532250531555
7101031421622
oct17032773077
95183558228
102020341311
1194748036a
12484736bbb
13262749c41
14152471db9
15bc57e9ab
hex786bf63f

2020341311 has 2 divisors, whose sum is σ = 2020341312. Its totient is φ = 2020341310.

The previous prime is 2020341299. The next prime is 2020341313. The reversal of 2020341311 is 1131430202.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2020341311 is a prime.

Together with 2020341313, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2020341311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2020341313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010170655 + 1010170656.

It is an arithmetic number, because the mean of its divisors is an integer number (1010170656).

Almost surely, 22020341311 is an apocalyptic number.

2020341311 is a deficient number, since it is larger than the sum of its proper divisors (1).

2020341311 is an equidigital number, since it uses as much as digits as its factorization.

2020341311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2020341311 is about 44948.2069831489. The cubic root of 2020341311 is about 1264.1780578138.

Adding to 2020341311 its reverse (1131430202), we get a palindrome (3151771513).

The spelling of 2020341311 in words is "two billion, twenty million, three hundred forty-one thousand, three hundred eleven".