Base | Representation |
---|---|
bin | 1001001100001100000011… |
… | …11011100101110111000000 |
3 | 2122120001112201102010220002 |
4 | 10212012001323211313000 |
5 | 10122110040224310422 |
6 | 110552202444335132 |
7 | 4154060444115524 |
oct | 446060173456700 |
9 | 78501481363802 |
10 | 20210001010112 |
11 | 6492016773151 |
12 | 2324a005444a8 |
13 | b37a44585074 |
14 | 4dc252685d84 |
15 | 250a96317692 |
hex | 126181ee5dc0 |
20210001010112 has 14 divisors (see below), whose sum is σ = 40104220754568. Its totient is φ = 10105000505024.
The previous prime is 20210001010103. The next prime is 20210001010123. The reversal of 20210001010112 is 21101010001202.
It is a junction number, because it is equal to n+sod(n) for n = 20210001010093 and 20210001010102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157890632828 + ... + 157890632955.
Almost surely, 220210001010112 is an apocalyptic number.
It is an amenable number.
20210001010112 is a deficient number, since it is larger than the sum of its proper divisors (19894219744456).
20210001010112 is an equidigital number, since it uses as much as digits as its factorization.
20210001010112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 315781265795 (or 315781265785 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 20210001010112 its reverse (21101010001202), we get a palindrome (41311011011314).
The spelling of 20210001010112 in words is "twenty trillion, two hundred ten billion, one million, ten thousand, one hundred twelve".
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