2021131115 has 4 divisors (see below), whose sum is σ = 2425357344. Its totient is φ = 1616904888.

The previous prime is 2021131109. The next prime is 2021131127. The reversal of 2021131115 is 5111311202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2021131115 - 2¹⁴ = 2021114731 is a prime.

It is a super-2 number, since 2×2021131115² = 8169941968042286450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2021131093 and 2021131102.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202113107 + ... + 202113116.

It is an arithmetic number, because the mean of its divisors is an integer number (606339336).

Almost surely, 2^2021131115 is an apocalyptic number.

2021131115 is a deficient number, since it is larger than the sum of its proper divisors (404226229).

2021131115 is an equidigital number, since it uses as much as digits as its factorization.

2021131115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 404226228.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 2021131115 is about 44956.9918366432. The cubic root of 2021131115 is about 1264.3427697204.

Adding to 2021131115 its reverse (5111311202), we get a palindrome (7132442317).

The spelling of 2021131115 in words is "two billion, twenty-one million, one hundred thirty-one thousand, one hundred fifteen".