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2022000001300 = 22521915731721383
BaseRepresentation
bin11101011011001000100…
…101111000000100010100
321011022010122201201020001
4131123020211320010110
5231112024000020200
64144521033221044
7266041021300366
oct35331045700424
97138118651201
102022000001300
1170a586318444
12287a63861784
1311889b3b6b16
146dc18630d36
15378e460b76a
hex1d6c8978114

2022000001300 has 144 divisors (see below), whose sum is σ = 4662972800640. Its totient is φ = 758913891840.

The previous prime is 2022000001297. The next prime is 2022000001303. The reversal of 2022000001300 is 31000002202.

It is an interprime number because it is at equal distance from previous prime (2022000001297) and next prime (2022000001303).

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2022000001303) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 94550409 + ... + 94571791.

It is an arithmetic number, because the mean of its divisors is an integer number (32381755560).

Almost surely, 22022000001300 is an apocalyptic number.

2022000001300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2022000001300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2331486400320).

2022000001300 is an abundant number, since it is smaller than the sum of its proper divisors (2640972799340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2022000001300 is a wasteful number, since it uses less digits than its factorization.

2022000001300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21890 (or 21883 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 10.

Adding to 2022000001300 its reverse (31000002202), we get a palindrome (2053000003502).

The spelling of 2022000001300 in words is "two trillion, twenty-two billion, one thousand, three hundred".

Divisors: 1 2 4 5 10 19 20 25 38 50 76 95 100 157 190 314 317 380 475 628 634 785 950 1268 1570 1585 1900 2983 3140 3170 3925 5966 6023 6340 7850 7925 11932 12046 14915 15700 15850 21383 24092 29830 30115 31700 42766 49769 59660 60230 74575 85532 99538 106915 120460 149150 150575 199076 213830 248845 298300 301150 406277 427660 497690 534575 602300 812554 945611 995380 1069150 1244225 1625108 1891222 2031385 2138300 2488450 3357131 3782444 4062770 4728055 4976900 6714262 6778411 8125540 9456110 10156925 13428524 13556822 16785655 18912220 20313850 23640275 27113644 33571310 33892055 40627700 47280550 63785489 67142620 67784110 83928275 94561100 127570978 128789809 135568220 167856550 169460275 255141956 257579618 318927445 335713100 338920550 515159236 637854890 643949045 677841100 1064210527 1275709780 1287898090 1594637225 2128421054 2575796180 3189274450 3219745225 4256842108 5321052635 6378548900 6439490450 10642105270 12878980900 20220000013 21284210540 26605263175 40440000026 53210526350 80880000052 101100000065 106421052700 202200000130 404400000260 505500000325 1011000000650 2022000001300